MathDB
ASU 466 All Soviet Union MO 1988 19 pos. <=88, 88 pos. <=19, same sum

Source:

August 7, 2019
algebracombinatoricsSumInteger sequenceSequence

Problem Statement

Given a sequence of 1919 positive integers not exceeding 8888 and another sequence of 8888 positive integers not exceeding 1919. Show that we can find two subsequences of consecutive terms, one from each sequence, with the same sum.
Back to ProblemsView on AoPS