MathDB
f(n)=n

Source: Moldova TST 2005

April 10, 2005
functionnumber theory unsolvednumber theory

Problem Statement

Given functions f,g:NNf,g:N^*\rightarrow N^*, gg is surjective and 2f(n)2=n2+g(n)22f(n)^2=n^2+g(n)^2, n>0\forall n>0. Prove that if f(n)n2005n|f(n)-n|\le2005\sqrt n, n>0\forall n>0, then f(n)=nf(n)=n for infinitely many nn.