Problem 2, Olympic Revenge 2013
Source: XII Olympic Revenge - 2013
January 26, 2013
geometrycircumcirclesimilar trianglesperpendicular bisector
Problem Statement
Let to be an acute triangle. Also, let and to be the two intersections of the perpendicular from with respect to side with the circle of diameter , with closer to than . Analogously, and are the two intersections of the perpendicular from with respect to side with the circle of diamter , with closer to than . Prove that the intersection of and lies on .