MathDB
Problems
Contests
National and Regional Contests
Bulgaria Contests
Bulgarian Autumn Mathematical Competition
2007 Bulgarian Autumn Math Competition
Problem 11.1
Trigonometric equation
Trigonometric equation
Source: 2007 Bulgarian Autumn Math Competition, Problem 11.1
March 17, 2022
algebra
Trigonometric Equations
Problem Statement
Let
0
<
α
,
β
<
π
2
0<\alpha,\beta<\frac{\pi}{2}
0
<
α
,
β
<
2
π
which satisfy
(
cos
2
α
+
cos
2
β
)
(
1
+
tan
α
tan
β
)
=
2
(\cos^2\alpha+\cos^2\beta)(1+\tan\alpha\tan\beta)=2
(
cos
2
α
+
cos
2
β
)
(
1
+
tan
α
tan
β
)
=
2
Prove that
α
+
β
=
π
2
\alpha+\beta=\frac{\pi}{2}
α
+
β
=
2
π
.
Back to Problems
View on AoPS