MathDB
2015-2016 Spring OMO #4

Source:

March 29, 2016
Online Math Open

Problem Statement

Given that xx is a real number, find the minimum value of f(x)=∣x+1∣+3∣x+3∣+6∣x+6∣+10∣x+10∣.f(x)=|x+1|+3|x+3|+6|x+6|+10|x+10|.
Proposed by Yannick Yao
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