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sin^2 x - 2 cos^2 x +\frac12 sin 2x = 0

Source: Spanish Mathematical Olympiad 1970 P7

December 4, 2022
trigonometry

Problem Statement

Calculate the values of the cosines of the angles xx that satisfy the next equation: sin⁡2x−2cos⁡2x+12sin⁡2x=0.\sin^2 x - 2 \cos^2 x +\frac12 \sin 2x = 0.
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