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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
610
Today's calculation of Integral 610
Today's calculation of Integral 610
Source:
June 2, 2010
calculus
integration
logarithms
calculus computations
Problem Statement
Evaluate
∫
2
a
x
a
−
1
−
x
a
x
ln
a
(
x
a
−
1
)
2
d
x
.
\int_2^a \frac{x^a-1-xa^x\ln a}{(x^a-1)^2}dx.
∫
2
a
(
x
a
−
1
)
2
x
a
−
1
−
x
a
x
l
n
a
d
x
.
proposed by kunny
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