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AMC 10
2011 AMC 10
1
Difference of two fractions
Difference of two fractions
Source: AMC 10 2011 b Problem 1
February 24, 2011
AMC
Problem Statement
What is
2
+
4
+
6
1
+
3
+
5
−
1
+
3
+
5
2
+
4
+
6
?
\frac{2+4+6}{1+3+5} - \frac{1+3+5}{2+4+6}?
1
+
3
+
5
2
+
4
+
6
−
2
+
4
+
6
1
+
3
+
5
?
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
a
n
>
−
1
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
a
n
>
5
36
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
a
n
>
7
12
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
a
n
>
147
60
<
s
p
a
n
c
l
a
s
s
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
a
n
>
43
3
<span class='latex-bold'>(A)</span>\ -1 \qquad <span class='latex-bold'>(B)</span>\ \frac{5}{36} \qquad <span class='latex-bold'>(C)</span>\ \frac{7}{12} \qquad <span class='latex-bold'>(D)</span>\ \frac{147}{60} \qquad <span class='latex-bold'>(E)</span>\ \frac{43}{3}
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
A
)
<
/
s
p
an
>
−
1
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
B
)
<
/
s
p
an
>
36
5
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
C
)
<
/
s
p
an
>
12
7
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
D
)
<
/
s
p
an
>
60
147
<
s
p
an
c
l
a
ss
=
′
l
a
t
e
x
−
b
o
l
d
′
>
(
E
)
<
/
s
p
an
>
3
43
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