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sin(2log_2 x)+tg(3log_2 x)=sin6+tg9 (V Soros Olympiad 1998-99 Round 3 11.1)

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May 26, 2024
algebratrigonometrylogarithms

Problem Statement

Find at least one root of the equationsin⁡(2log⁡2x)+tg(3log⁡2x)=sin⁡6+tg9\sin(2 \log_2 x) + tg(3\log_2 x) = \sin6+tg9less than 0.010.01.
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