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x^3 +y^3 = 4(x^2y+xy^2 +1) NT All-Russian MO 1993 Regional (R4) 9.5

Source:

August 26, 2024
number theorydiophantine

Problem Statement

Show that the equation x3+y3=4(x2y+xy2+1)x^3 +y^3 = 4(x^2y+xy^2 +1) has no integer solutions.