MathDB
Cevian and Equal Perimeters

Source:

September 7, 2024
geometry2024

Problem Statement

Triangle JHUJHU has side lengths JH=13JH=13, HU=14HU=14, and JU=15JU=15. Point XX lies on HU\overline{HU} such that JHX\triangle{JHX} and JUX\triangle{JUX} have equal perimeters. Compute JX2JX^2.