MathDB
A nice limit

Source: flanders '87

September 24, 2005
limitinequalities

Problem Statement

Show that for p>1p>1 we have limn+1p+2p+...+(n1)p+np+(n1)p+...+2p+1pn2=+\lim_{n\rightarrow+\infty}\frac{1^p+2^p+...+(n-1)^p+n^p+(n-1)^p+...+2^p+1^p}{n^2} = +\infty Find the limit if p=1p=1.