MathDB
weird ratio in a cyclic quad

Source: Bulgarian Spring Tournament 2023 11.2

March 25, 2023
geometry

Problem Statement

Given is a cyclic quadrilateral ABCDABCD and a point EE lies on the segment DADA such that 2EBD=ABC2\angle EBD = \angle ABC. Prove that DE=AC.BDAB+BCDE= \frac {AC.BD}{AB+BC}.