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Angle chasing with 30 and 39 degree

Source:

February 23, 2019
geometryAngle Chasing

Problem Statement

ABC\triangle ABC is isosceles AB=ACAB = AC. PP is a point inside ABC\triangle ABC such that BCP=30\angle BCP = 30 and APB=150\angle APB = 150 and CAP=39\angle CAP = 39. Find BAP\angle BAP.