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sin^2c = sin^2a + sin^2b

Source: 1994 Swedish Mathematical Competition p3

April 2, 2021
trigonometrygeometry

Problem Statement

The vertex BB of the triangle ABCABC lies in the plane PP. The plane of the triangle meets the plane in a line LL. The angle between LL and ABAB is a, and the angle between LL and BCBC is bb. The angle between the two planes is cc. Angle ABCABC is 90o90^o. Show that sin2c=sin2a+sin2b\sin^2c = \sin^2a + \sin^2b. https://cdn.artofproblemsolving.com/attachments/9/e/c0608e5408fd27a5f907a3488cce7dc2af6953.png