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2017 BMT Spring
20
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2017 BMT Individual 20
Source:
January 9, 2022
algebra
Problem Statement
Evaluate
∑
k
=
0
15
(
2
560
(
−
1
)
k
cos
560
(
k
π
16
)
)
(
m
o
d
17
)
.
\sum^{15}_{k=0}\left(2^{560}(-1)^k \cos^{560}\left( \frac{k\pi}{16}\right)\right) \pmod{17}.
∑
k
=
0
15
(
2
560
(
−
1
)
k
cos
560
(
16
kπ
)
)
(
mod
17
)
.
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