MathDB
[x+1/x] = [x^2+1/x^2]

Source: 2019 Romania District VIII p4

September 1, 2024
algebrafloor functionInteger Part

Problem Statement

Solve the equation in the set of real numbers: [x+1x]=[x2+1x2]\left[ x+\frac{1}{x} \right] = \left[ x^2+\frac{1}{x^2} \right] where [a][a], represents the integer part of the real number aa.
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