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x^3 + y^3 + z^3 − 3xyz = 2003

Source: Nordic Mathematical Contest 2003 #2

September 24, 2017

number theorycubic equationinteger equation

Problem Statement

Find all triples of integers

{(x, y, z)}

satisfying

{x^3 + y^3 + z^3 - 3xyz = 2003}