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CCA Math Bonanza
2022 CCA Math Bonanza
I7
Subset Bashing
Subset Bashing
Source:
April 26, 2022
Problem Statement
Let
A
=
{
2
,
4
,
…
,
1000
}
,
A = \{2, 4, \ldots, 1000\},
A
=
{
2
,
4
,
…
,
1000
}
,
B
=
{
3
,
6
,
…
,
999
}
,
B = \{3, 6, \ldots, 999\},
B
=
{
3
,
6
,
…
,
999
}
,
C
=
{
5
,
10
,
…
,
1000
}
,
C = \{5, 10, \ldots, 1000\},
C
=
{
5
,
10
,
…
,
1000
}
,
D
=
{
7
,
14
,
…
,
994
}
,
D = \{7, 14, \ldots, 994\},
D
=
{
7
,
14
,
…
,
994
}
,
E
=
{
11
,
22
,
…
,
990
}
,
E = \{11, 22, \ldots, 990\},
E
=
{
11
,
22
,
…
,
990
}
,
and
F
=
{
13
,
26
,
…
,
988
}
.
\textrm{and } F = \{13, 26, \ldots, 988\}.
and
F
=
{
13
,
26
,
…
,
988
}
.
Find the number of elements in the set
(
(
(
(
(
A
∪
B
)
∩
C
)
∪
D
)
∩
E
)
∪
F
)
(((((A\cup B)\cap C)\cup D)\cap E)\cup F)
(((((
A
∪
B
)
∩
C
)
∪
D
)
∩
E
)
∪
F
)
. 2022 CCA Math Bonanza Individual Round #7
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