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The 3-4-5 homothety bisection (BMT 2019 Geo #6)

Source:

May 12, 2019
geometrygeometric transformationhomothety

Problem Statement

Let ABE \triangle ABE be a triangle with AB3=BE4=EA5 \frac{AB}{3} = \frac{BE}{4} = \frac{EA}{5} . Let DA D \neq A be on line AE \overline{AE} such that AE=ED AE = ED and D D is closer to E E than to A A . Moreover, let C C be a point such that BCDE BCDE is a parallelogram. Furthermore, let M M be on line CD \overline{CD} such that AM \overline{AM} bisects BAE \angle BAE , and let P P be the intersection of AM \overline{AM} and BE \overline{BE} . Compute the ratio of PM PM to the perimeter of ABE \triangle ABE .