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Today's Calculation Of Integral
2010 Today's Calculation Of Integral
664
Today's calculation of Integral 664
Today's calculation of Integral 664
Source:
January 12, 2011
calculus
integration
trigonometry
calculus computations
Problem Statement
For a positive integer
n
n
n
, let
I
n
=
∫
−
π
π
(
π
2
−
∣
x
∣
)
cos
n
x
d
x
I_n=\int_{-\pi}^{\pi} \left(\frac{\pi}{2}-|x|\right)\cos nx\ dx
I
n
=
∫
−
π
π
(
2
π
−
∣
x
∣
)
cos
n
x
d
x
.Find
I
1
+
I
2
+
I
3
+
I
4
I_1+I_2+I_3+I_4
I
1
+
I
2
+
I
3
+
I
4
.1992 University of Fukui entrance exam/Medicine
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