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2019 MMATHS Tiebreaker p4 - c^2f(x + y) = f(x)f(y), continuous f

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October 7, 2023
functional equationalgebra

Problem Statement

The continuous function f(x)f(x) satisfies c2f(x+y)=f(x)f(y)c^2f(x + y) = f(x)f(y) for all real numbers xx and y,y, where c>0c > 0 is a constant. If f(1)=cf(1) = c, find f(x)f(x) (with proof).