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ASU 098 All Soviet Union MO 1968 2/(x^2-1)+..+20/(x^2-100)= ..

Source:

June 20, 2019
algebra

Problem Statement

Prove the equality 2x21+4x24+6x29+...+20x2100=11(x1)(x+10)+11(x2)(x+9)+...+11(x10)(x+1)\frac{2}{x^2-1}+\frac{4}{x^2-4} +\frac{6}{x^2-9}+...+\frac{20}{x^2-100} =\frac{11}{(x-1)(x+10)}+\frac{11}{(x-2)(x+9)}+...+\frac{11}{(x-10)(x+1)}