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Show that there exist a polynomial P(x)

Source: MTRP 2016 Class 11-Short Answer Type Question: Problem 1 :-

May 31, 2020
algebrapolynomial

Problem Statement

Show that there exist a polynomial P(x)P(x) whose one cofficient is 12016\frac{1}{2016} and remaining cofficients are rational numbers, such that P(x)P(x) is an integer for any integer xx .
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