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7
SMT 2010 Algebra Problem 7
SMT 2010 Algebra Problem 7
Source:
July 27, 2011
Problem Statement
Find all the integers
x
x
x
in
[
20
,
50
]
[20, 50]
[
20
,
50
]
such that
6
x
+
5
≡
−
19
m
o
d
10
,
6x + 5 \equiv -19 \mod 10,
6
x
+
5
≡
−
19
mod
10
,
that is,
10
10
10
divides
(
6
x
+
15
)
+
19.
(6x + 15) + 19.
(
6
x
+
15
)
+
19.
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