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Serbia Junior TST 2016

Source: Serbia Junior TST 2016 P4

May 21, 2016
Inequalityinequalities

Problem Statement

Let a,b,cR+a,b,c\in \mathbb{R}^+, prove that: 2a3a+b+2b3b+c+2c3c+a3(a+b+c)\frac{2a}{\sqrt{3a+b}}+\frac{2b}{\sqrt{3b+c}}+\frac{2c}{\sqrt{3c+a}}\leq \sqrt{3(a+b+c)}