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angles equal 180

Source: Olimpiada Rioplatense 2015-Level 3-Problem 1

July 1, 2016
geometry

Problem Statement

Let ABCABC be a triangle and PP a point on the side BCBC. Let S1S_1 be the circumference with center BB and radius BPBP that cuts the side ABAB at DD such that DD lies between AA and BB. Let S2S_2 be the circumference with center CC and radius CPCP that cuts the side ACAC at EE such that EE lies between AA and CC. Line APAP cuts S1S_1 and S2S_2 at XX and YY different from PP, respectively. We call TT the point of intersection of DXDX and EYEY. Prove that BAC+2DTE=180\angle BAC+ 2 \angle DTE=180