Triangle PAB is formed by three tangents to circle O and < APB \equal{} 40^{\circ}; then angle AOB equals:
<spanclass=′latex−bold′>(A)</span>45∘<spanclass=′latex−bold′>(B)</span>50∘<spanclass=′latex−bold′>(C)</span>55∘<spanclass=′latex−bold′>(D)</span>60∘<spanclass=′latex−bold′>(E)</span>70∘