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2019 Taiwan APMO Preliminary P7

Source: 2019 Taiwan APMO Preliminary

August 23, 2020
combinatoricsSequencealgebra

Problem Statement

Let positive integer kk satisfies 1<k<1001<k<100. For the permutation of 1,2,...,1001,2,...,100 be a1,a2,...,a100a_1,a_2,...,a_{100}, take the minimum m>km>k such that ama_m is at least less than (k1)(k-1) numbers of a1,a2,...,aka_1,a_2,...,a_k. We know that the number of sequences satisfies am=1a_m=1 is 100!4\frac{100!}{4}. Find the all possible values of kk.