MathDB
1994 AMC 12 #27

Source:

December 30, 2011
abstract algebraprobabilityAMC

Problem Statement

A bag of popping corn contains 23\frac{2}{3} white kernels and 13\frac{1}{3} yellow kernels. Only 12\frac{1}{2} of the white kernels will pop, whereas 23\frac{2}{3} of the yellow ones will pop. A kernel is selected at random from the bag, and pops when placed in the popper. What is the probability that the kernel selected was white?
<spanclass=latexbold>(A)</span> 12<spanclass=latexbold>(B)</span> 59<spanclass=latexbold>(C)</span> 47<spanclass=latexbold>(D)</span> 35<spanclass=latexbold>(E)</span> 23 <span class='latex-bold'>(A)</span>\ \frac{1}{2} \qquad<span class='latex-bold'>(B)</span>\ \frac{5}{9} \qquad<span class='latex-bold'>(C)</span>\ \frac{4}{7} \qquad<span class='latex-bold'>(D)</span>\ \frac{3}{5} \qquad<span class='latex-bold'>(E)</span>\ \frac{2}{3}