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Tie 3
2021 BMT Algebra Tiebreaker #3
2021 BMT Algebra Tiebreaker #3
Source:
March 10, 2024
algebra
inequalities
Problem Statement
For integers
a
a
a
and
b
b
b
,
a
+
b
a + b
a
+
b
is a root of
x
2
+
a
x
+
b
=
0
x^2 + ax + b = 0
x
2
+
a
x
+
b
=
0
. Compute the smallest possible value of
a
b
ab
ab
.
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