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Soros Olympiad in Mathematics
III Soros Olympiad 1996 - 97 (Russia)
10.1
1^o in terms of cos 157^o = a (III Soros Olympiad 1996-97 R2 10.1)
1^o in terms of cos 157^o = a (III Soros Olympiad 1996-97 R2 10.1)
Source:
May 31, 2024
trigonometry
Problem Statement
It is known that
cos
15
7
o
=
a
\cos 157^o = a
cos
15
7
o
=
a
, where
a
a
a
is given. Calculate
1
o
1^o
1
o
in terms of
a
a
a
.
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