The number of ordered pairs of integers (m,n) for which mn≥0 and m^3 \plus{} n^3 \plus{} 99mn \equal{} 33^3 is equal to<spanclass=′latex−bold′>(A)</span>2<spanclass=′latex−bold′>(B)</span>3<spanclass=′latex−bold′>(C)</span>33<spanclass=′latex−bold′>(D)</span>35<spanclass=′latex−bold′>(E)</span>99