Today's calculation of Integral 303
Source: 2008 Tokyo University entrance exam/Science, Problem 6
February 25, 2008
calculusintegrationgeometrytrigonometrycalculus computations
Problem Statement
In the x \minus{} y plane, find the area of the region bounded by the parameterized curve as follows.
\left\{\begin{array}{ll} x \equal{} \cos 2t & \\
y \equal{} t\sin t & \end{array} \right.\ (0\leq t\leq 2\pi)