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Today's calculation of Integral 611

Source:

June 18, 2010
calculusintegrationderivativelogarithmsfunctioninequalitiessearch

Problem Statement

Let g(t)g(t) be the minimum value of f(x)=x2−xf(x)=x2^{-x} in t≤x≤t+1t\leq x\leq t+1. Evaluate ∫02g(t)dt\int_0^2 g(t)dt.
2010 Kumamoto University entrance exam/Science
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