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Determinant of sum of matrix with its adjugate

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October 31, 2019
linear algebramatrix

Problem Statement

Let be a natural number n n and a n×n n\times n nilpotent real matrix A. A. Prove that 0=det⁡(A+adjA). 0=\det\left( A+\text{adj} A \right) .
Neculai Moraru
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