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no of harmonic triples (a, b, c) is equal to the no of positive divisor of c^2

Source: 2001 Estonia National Olympiad Final Round grade 10 p4

March 12, 2020
number theoryharmonicDivisors

Problem Statement

We call a triple of positive integers (a,b,c)(a, b, c) harmonic if 1a=1b+1c\frac{1}{a}=\frac{1}{b}+\frac{1}{c}. Prove that, for any given positive integer cc, the number of harmonic triples (a,b,c)(a, b, c) is equal to the number of positive divisors of c2c^2.