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Point inside parallelogram

Source: Canadian Mathematical Olympiad - 1997 - Problem 4.

May 7, 2011
geometryparallelogramgeometry solvedAngle ChasingCanadaCMO

Problem Statement

The point OO is situated inside the parallelogram ABCDABCD such that ∠AOB+∠COD=180∘\angle AOB+\angle COD=180^{\circ}. Prove that ∠OBC=∠ODC\angle OBC=\angle ODC.
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