MathDB
Prove angle ADB=3angleBAC if AE=CD

Source: KJMO 2019 p2

January 8, 2021
geometryKJMO

Problem Statement

In an acute triangle ABCABC, point DD is on the segment ACAC such that AD=BC\overline{AD}=\overline{BC} and AC2AD2=ACAD\overline{AC}^2-\overline{AD}^2=\overline{AC}\cdot\overline{AD}. The line that is parallel to the bisector of ACB\angle{ACB} and passes the point DD meets the segment ABAB at point EE. Prove, if AE=CD\overline{AE}=\overline{CD}, ADB=3BAC\angle{ADB}=3\angle{BAC}.