MathDB

The Order "For Faithful Service" of the

7

th degree in shape is a combination of a semicircle with a diameter

AB = 2

and a triangle

AM B

. The sides

AM

and

BM

intersect the semicircle (the border of the semicircle). The part of the circle outside the triangle and the part of the triangle outside the circle are made of pure copper. What should the side of the triangle be equal to in order for the area of the copper part to be the smallest?

Problem Statement