MathDB
Associating AB to A'B'

Source:

June 13, 2009
ratio

Problem Statement

In this diagram a scheme is indicated for associating all the points of segment AB \overline{AB} with those of segment AB \overline{A'B'}, and reciprocally. To described this association scheme analytically, let x x be the distance from a point P P on AB \overline{AB} to D D and let y y be the distance from the associated point P P' of AB \overline{A'B'} to D D'. Then for any pair of associated points, if x \equal{} a,\, x \plus{} y equals: [asy]defaultpen(linewidth(.8pt)); unitsize(.8cm);
pair D= (0,9); pair E = origin; pair A = (3,9); pair P = (3.6,9); pair B = (4,9); pair F = (1,0); pair G = (2.6,0); pair H = (5,0);
dot((0,0));dot((1,0));dot((2,0));dot((3,0));dot((4,0));dot((5,0)); dot((0,9));dot((1,9));dot((2,9));dot((3,9));dot((4,9));dot((5,9)); draw((D+(0,0.5))--(0,-0.5)); draw(A--H); draw(P--G); draw(B--F); draw(F--H); draw(A--B);
label("DD",D,NW); label("DD'",E,NW); label("0",(0,0),SE); label("1",(1,0),SE); label("2",(2,0),SE); label("3",(3,0),SE); label("4",(4,0),SE); label("5",(5,0),SE); label("0",(0,9),SE); label("1",(1,9),SE); label("2",(2,9),SE); label("3",(3,9),SW); label("4",(4,9),SE); label("5",(5,9),SE); label("BB'",F,NW); label("PP'",G,S); label("AA'",H,NE); label("AA",A,NW); label("PP",P,N); label("BB",B,NE);[/asy] (A)\ 13a\qquad (B)\ 17a \minus{} 51\qquad (C)\ 17 \minus{} 3a\qquad (D)\ \frac {17 \minus{} 3a}{4}\qquad (E)\ 12a \minus{} 34