MathDB
Today's calculation of Integral 41

Source: 1988 Wakayama Medical University

June 10, 2005
calculusintegrationtrigonometryderivativegeometrycalculus computations

Problem Statement

Evaluate ∫0a2ax−x2 dx (a>0)\int_0^a \sqrt{2ax-x^2}\ dx \ (a>0)
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