Purple Comet 2009 HS Problem 23
Source:
April 21, 2012
geometryrectangleprobabilitynumber theoryrelatively prime
Problem Statement
Square has side length . Points and are the midpoints of sides and , respectively. Eight by rectangles are placed inside the square so that no two of the eight rectangles overlap (see diagram). If the arrangement of eight rectangles is chosen randomly, then there are relatively prime positive integers and so that is the probability that none of the rectangles crosses the line segment (as in the arrangement on the right). Find .[asy]
size(200);
defaultpen(linewidth(0.8)+fontsize(10pt));
real r = 7;
path square=origin--(4,0)--(4,4)--(0,4)--cycle;
draw(square^^shift((r,0))*square,linewidth(1));
draw((1,4)--(1,0)^^(3,4)--(3,0)^^(0,2)--(1,2)^^(1,3)--(3,3)^^(1,1)--(3,1)^^(2,3)--(2,1)^^(3,2)--(4,2));
draw(shift((r,0))*((2,4)--(2,0)^^(0,2)--(4,2)^^(0,1)--(4,1)^^(0,3)--(2,3)^^(3,4)--(3,2)));
label("A",(4,4),NE);
label("A",(4+r,4),NE);
label("B",(0,4),NW);
label("B",(r,4),NW);
label("C",(0,0),SW);
label("C",(r,0),SW);
label("D",(4,0),SE);
label("D",(4+r,0),SE);
label("E",(2,4),N);
label("E",(2+r,4),N);
label("F",(2,0),S);
label("F",(2+r,0),S);
[/asy]