MathDB
Today's calculation of integral 90

Source: 1988 Tokyo Institute of Technology entrance exam

November 16, 2005
calculusintegrationlimitlogarithmsfactorialfunctionratio

Problem Statement

Find limn(3nCn2nCn)1n\lim_{n\to\infty} \left(\frac{_{3n}C_n}{_{2n}C_n}\right)^{\frac{1}{n}} where iCj_iC_j is a binominal coefficient which means i(i1)(ij+1)j(j1)21\frac{i\cdot (i-1)\cdots(i-j+1)}{j\cdot (j-1)\cdots 2\cdot 1}.