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National and Regional Contests
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MAA AMC
AMC 12/AHSME
1966 AMC 12/AHSME
1
Ratios
Ratios
Source:
March 9, 2006
ratio
Problem Statement
Given that the ratio of
3
x
−
4
3x-4
3
x
−
4
to
y
+
15
y+15
y
+
15
is constant, and
y
=
3
y=3
y
=
3
when
x
=
2
x=2
x
=
2
, then, when
y
=
12
y=12
y
=
12
,
x
x
x
equals:
(A)
1
8
(B)
7
3
(C)
7
8
(D)
7
2
(E)
8
\text{(A)} \ \frac 18 \qquad \text{(B)} \ \frac 73 \qquad \text{(C)} \ \frac78 \qquad \text{(D)} \ \frac72 \qquad \text{(E)} \ 8
(A)
8
1
(B)
3
7
(C)
8
7
(D)
2
7
(E)
8
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