MathDB

x^2y^2(x^2+y^2)<=2 if x, y>=0 and x+y= 2

Source: 2001 Estonia National Olympiad Final Round grade 11 p1

March 12, 2020

inequalitiesalgebra

Problem Statement

x

and

y

are nonnegative real numbers with

x+y= 2

, show that

x^2y^2(x^2+y^2)\le 2