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distance from point p to longest side h is less than or equal to s/\sqrt3

Source: Norwegian Mathematical Olympiad 2013 - Abel Competition p2

September 4, 2019
distancecombinatorial geometrycombinatoricsgeometry

Problem Statement

In a triangle TT, all the angles are less than 90o90^o, and the longest side has length ss. Show that for every point pp in TT we can pick a corner hh in TT such that the distance from pp to hh is less than or equal to s/3s/\sqrt3.