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P(x)^2+1=(x^2+1)Q(x^2), der(P)=?

Source: 10th European Mathematical Cup - Problem S4

December 22, 2021
polynomialalgebraEuropean Mathematical Cup

Problem Statement

Find all positive integers dd for which there exist polynomials P(x)P(x) and Q(x)Q(x) with real coefficients such that degree of PP equals dd and P(x)2+1=(x2+1)Q(x)2.P(x)^2+1=(x^2+1)Q(x)^2.