MathDB
Coinciding orthocenters

Source: Bulgarian IMO TST 2004, Day 2, Problem 2

July 8, 2013
geometrycircumcirclegeometric transformationreflectionrotationtrapezoidpower of a point

Problem Statement

Let HH be the orthocenter of ABC\triangle ABC. The points A1AA_{1} \not= A, B1BB_{1} \not= B and C1CC_{1} \not= C lie, respectively, on the circumcircles of BCH\triangle BCH, CAH\triangle CAH and ABH\triangle ABH and satisfy A1H=B1H=C1HA_{1}H=B_{1}H=C_{1}H. Denote by H1H_{1}, H2H_{2} and H3H_{3} the orthocenters of A1BC\triangle A_{1}BC, B1CA\triangle B_{1}CA and C1AB\triangle C_{1}AB, respectively. Prove that A1B1C1\triangle A_{1}B_{1}C_{1} and H1H2H3\triangle H_{1}H_{2}H_{3} have the same orthocenter.