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Scientific Notation

Source: 1993 AMC 8 Problem 4

June 28, 2011
AMC

Problem Statement

1000×1993×0.1993×10=1000\times 1993 \times 0.1993 \times 10 =
(A) 1.993×103(B) 1993.1993(C) (199.3)2(D) 1,993,001.993(E) (1993)2\text{(A)}\ 1.993\times 10^3 \qquad \text{(B)}\ 1993.1993 \qquad \text{(C)}\ (199.3)^2 \qquad \text{(D)}\ 1,993,001.993 \qquad \text{(E)}\ (1993)^2
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